VITEEE 2017 Paper

The given lines are,
y - 1 = x , x ≥ 0 ; y - 1 = - x , x > 0
y = 0 ; x = -

1

2

, x < 0 ; x =

1

2

, x ≥ 0
so that the area bounded is as shown in the figure.

Required area = 2∫01∕2 (1 + x) dx
= 2(x+

x2

2

)01∕2 = 2 (

1

2

+

1

8

) =

5

4