VITEEE 2017 Paper

The power dissipated in the circuit.
P =

V2

Req

... (i)
v = 10 volt

1

Req

=

1

R

+

1

5

=

5+R

5R

Req = (

5R

5+R

)
P = 30 W
Substituting the values in equation (i)
30 =

(10)2

( 5R 5+R )

15R

5+R

= 10 ⇒ 15 R = 50 + 10 R
5R = 50 ⇒ R = 10 Ω