If the eccentricity of the hyperbola x^2-y^2 cosec^2 α = 25 is \sqrt5 times the eccentricity of the ellipse x^2 cosec^2 \alpha + y^2 = 5 , then α is equal to :

Correct Answer is : tan−1√2

VITEEE 2017 Paper

Section: Aptitude

Question : 114 of 125

Marks: +1, -0

If the eccentricity of the hyperbola
x2−y2cosec2 α = 25 is √5 times the eccentricity of the ellipse x2cosec2α+y2 = 5 , then α is equal to :

Go to Question:

Prev Question

Next Question