VITEEE 2017 Paper

Let the line be

x

a

=

y

b

=

z

c

... (i)
If line (i) intersects with the line

x−1

2

= y+

3

4

=

z−5

3

, then
|

a	b	c
2	4	3
4	−3	14

| = 0
⇒ 9a - 7b - 10c = 0 ... (ii)
from (i) and (ii), we have

a

1

=

b

−3

=

x

5

∴ The line is

x

1

=

y

−3

=

z

5