The solution of the differential equation (1+y^2) + (x-e^{\tan^{-1}y}) \frac{dy}{dx} = 0

Correct Answer is : 2 xetan−1y = e2tan−1y + k

2 xe^{\tan^{-1}y} = e^{2tan^{-1}y} + k

xe^{\tan^{-1}y} = \tan^{-1} y + k

xe^{2tan^{-1}y} = e^{\tan^{-1}y} + k

VITEEE 2016 Paper

Section: Mathematics

Question : 81 of 125

Marks: +1, -0

The solution of the differential equation
(1+y2) + (x−etan−1y)

= 0

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