VITEEE 2016 Paper

Section: Physics

Question : 2 of 125

Marks: +1, -0

In photoelectric effect, initially when energy of electrons emitted is E0, de-Broglie wavelength associated with them is λ0. Now, energy is doubled then associated de-Broglie wavelength λ' is

λ' =
λ0
√2
λ' = √2λ0
λ' = λ0
λ' =
λ0
2

Validate

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