VITEEE 2016 Paper

An equivalent of the given network is as shown in the figure. If Rp be the net resistance, then

1

Rp

=

1

10

+(

1

10+10

) + (

1

10+10

) +

1

10

=

1

10

+

1

20

+

1

20

+

1

10

=

6

20

=

3

10

∴ Rp =

10

3

Ω
Hence, current flowing through ammeter is
I =

V

Rp

=

12

( 10 3 )

= 3.6 A