Two light rays having the same wavelength in vacuum are in phase initially Then, the first ray travels a path through a medium of refractive index \mu_1 while the second ray travels a path L_2 through a medium of refractive index \mu_2. The two waves are then combined to observe interference. The phase difference between the two waves is

Correct Answer is : 2πλ(µ1L1−µ2L2)

{2\pi}/\lambda (L_1/\mu_1-L_2/\mu_2)

{2\pi}/\lambda (\mu_2L_1-\mu_1L_2)

{2\pi}/\lambda (\mu_1L_1-\mu_2L_2)

VITEEE 2015 Paper

Section: Physics

Question : 35 of 120

Marks: +1, -0

Two light rays having the same wavelength in vacuum are in phase initially Then, the first ray travels a path through a medium of refractive index µ1 while the second ray travels a path L2 through a medium of refractive index µ2. The two waves are then combined to observe interference. The phase difference between the two waves is

2π
λ
(
L1
µ1
−
L2
µ2
)
2π
λ
(L2−L1)
2π
λ
(µ2L1−µ1L2)
2π
λ
(µ1L1−µ2L2)

Validate

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