VITEEE 2015 Paper

Equation of hyperbola is
3x2−2y2 = 6
⇒

x2

2

−

y2

3

= 1
So , a2 = 2 and b2 = 3
Given, equation of line is x - 3y = 3.
∴ Slope of given line =

1

3

∴ Slope of line perpendicular to given line, m = -3
The equation of tangents are
y = mx ± √a2m2−b2
= - 3x ± √2×9−3
= - 3x ± √18−3
= - 3x ± √15