VITEEE 2014 Paper

It is known,

(t1∕2)1

(t1∕2)2

= [

a2

a1

](n−1)
Here, n = order of the reaction
Given , (t1∕2)1 = 0.1 s , a1 400
(t1∕2)2 = 0.8 s , a2 = 50
On putting the values,

0.1

0.8

= [

50

400

](n−1)
Taking log on both sides
log

0.1

.8

= (n - 1) log

50

400

log

1

8

= (n - 1) log

1

8

n - 1 = 1 ⇒ n = 2