lf l (m, n) = \int^{1}_{0} t^m (1+t)^n dt , then the expression for l (m, n) in terms of l (m + 1, n + 1) is

Correct Answer is : 2nm+1−nm+1 . l (m + 1 , n - 1)

2^n/{m+1} - n/{m+1} . l (m + 1 , n - 1)

\frac{2n}{m+1} - n/{m+1} . l (m + 1 , n - 1)

\frac{m}{n+1} . l (m + 1 , n - 1)

VITEEE 2014 Paper

Section: Mathematics

Question : 118 of 120

Marks: +1, -0

lf l (m, n) =

∫

tm(1+t)n dt , then the expression for l (m, n) in terms of l (m + 1, n + 1) is

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