VITEEE 2014 Paper

On homogenising y2−x2 = 4 with the √3 x + y = 2 , we get
y2−x2 = 4

(√3x+y)2

4

⇒ y2−x2 = 3x2+y2+2√3 xy
⇒ 4x2+2√3 xy =
On comparing with ax2 + 2hxy + by2 = 0 ,
we get
a = 4 , h = √3 and b = 0
We know that.
tan θ = 2

√h2−ab

a+b

=

2.√3−0

4+0

∴ The angle between the lines is
θ = tan−1(

√3

√2

)