VITEEE 2014 Paper

x−1

2

=

y+1

3

=

z−1

4

= r (say)
⇒ x = 2r+ 1 ,y = 3r - 1 ,z = 4r + 1
Since, the two lines intersect.
So, putting above values in second line, we get

2r+1−3

1

=

3r−1−k

2

=

4r+1

1

2r - 2 = 4r + 1
⇒ r = - 3/2
Also 3r - 1 - k = 8r + 2
⇒ k = - 5r - 3 =

15

3

- 3 =

9

2