VITEEE 2013 Paper

For Cu wire , , l1 = 2.2 m , r1 = 1.5 mm
= 1.5 × 10−3 n
Y1 = 1.1 × 1011 N/m2
For steel wire l2 = 1.6 m , r2 = 1.5 mm
= 1.5 × 10−3 m
Y2 = 2.0 × 1011 N/m2
Let F be the stretching force in both the wires the
For Cu wire, Y1 =

F

πr12

×

l1

Δl1

⇒ F =

Y1πr12×Δl1

l1

=

1.1×10−11

2.2

×

22

7

× (1.5×10−3)2 × 0.5 × 103
= 1.8 x 102 N