Acid hydrolysis of ester is first order reaction and rate constant is given by k = {2.303}/t log \frac{V_\infty-V_0}{V_\infty-V_t} where , V_ , V_t and V_\infty are the volumle of standard NaOH required to neutralise acid present at a given time, if ester is 50% neutralised then

Correct Answer is : V∞ = 2Vt−V0

VITEEE 2013 Paper

Section: Chemistry

Question : 61 of 120

Marks: +1, -0

Acid hydrolysis of ester is first order reaction and rate constant is given by k =

2.303

log

V∞−V0

V∞−Vt

where , V,Vt and V∞ are the volumle of standard NaOH required to neutralise acid present at a given time, if ester is 50% neutralised then

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