VITEEE 2013 Paper

Given, y = 3 sin π (

t

2

−

x

4

)
= 3 sin (

πt

2

−

πx

4

)
Comparing it with standard equation
y = r sin

2π

λ

(vt - x)
= r sin (

2πvt

λ

−

2πx

λ

)
We have,

2πv

λ

=

π

2

or v =

λ

4

and

2π

4

=

π

4

or λ = 8m
∴ v =

8

4

= 2 m/s
So, the distance travelled by wave in t second = vt = 2 x 5 = 10 m