VITEEE 2012 Paper

Center is the point of intersection of diagonals.
⇒2x−3y=5......(i)
⇒3x−4y=7........(ii)
are diameter of circle so, point of intersection is centre of circle.from (1) & (2), x=1, y=−1
∴ area of circle is 154
=πr2=154
r2=

7

22

×154
=

7×14

2

r2=49 ⇒ r = 7
∴ Equation of circle with centre (1,−1) and radius 7 units
⇒(x−1)2+(y+1)2=72
⇒x2+1−2x+y2+1+2y=49
⇒x2+y2−2x+2y=49−2
⇒x2+y2−2x+2y=47