VITEEE 2012 Paper

f(x) = (x - 1)(x - 2)(x - 3)
⇒ f(1) = f(2) = f(3) = 0
∴ f(x) is not one-one.
For each y e R, there exists x ∊ R such that f(x) = y.
∴ f is onto.
Note that if a continuous function has more than one roots, then the function is always many-one.