VITEEE 2012 Paper

Section: Chemistry

Question : 49 of 120

Marks: +1, -0

The reaction,
2A (g) + B (g) ⇄ 3C (g) + D (g)
is begun with the concentrations of A and B both at an initial value of 1.00 M. When equilibrium is reached, the concentration of D is measured and found to be 0.25 M. The value for the equilibrium constant for this reaction is given by the expression

[(0.75)3 (0.25)] + [(1.00)2 (1.00)]
[(0.75)3 (0.25)] + [(0.50)2 (0.75)]
[(0.75)3 (0.25)] + [(0.50)2 (0.25)]
[(0.75)3 (0.25)] + [(0.75)2 (0.25)]

Validate

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Initial	1	1	0	0
At‌equilibrium	1−0.50	1−0.25	0.75	0.25