VITEEE 2012 Paper

The arrangement is shown in figure.

Here, two reisistance of 1Ω and 2Ω are in series, which form 3Ω which is in parallel with 3Ω resistance.
Therefore, the effective resistance

(1+2)×3

(1+2)+3

=

3

2

Ω

∴ Current in the circuit,
I =

3

(3∕2)

= 2A
∴ Current in 3 Ω resistor =

I

2

= 1 A