VITEEE 2012 Paper

The intersection point of lines x - 2y = 1
and x + 3y = 2 is (

7

5

,

1

5

)
Since, required line is parallel to 3x+4y = 0.
Therefore, the slope of required line is −

3

4

.
∴ Equation of required line which passes through (

7

5

,

1

5

) is given by
y -

1

5

= -

3

4

(x−

7

5

)
⇒

3x

4

+ y =

21

20

+

1

5

⇒ 3x + 4y - 5 = 0