VITEEE 2011 Paper

α, β . γ are the roots of given equation,
Therefore α + β + γ = - a
αβ + βγ + γα = 0
and αβγ = - b
Now, |

α	β	γ
β	γ	α
γ	α	β

| = - (α + β + γ)
(α2+β2+γ2 - αβ - βγ - γα)
= - (α + β + γ) [(α+β+γ)2 - 3 (αβ + βγ γα)]
= - (- a) (a2−0) = a3