VITEEE 2010 Paper

Let ‌L1=2x+y−1=0
L2=3x+2y−5=0
The equation of straight line passing through the intersection point of the line L1‌and‌L2 is gven by
L1+λL2=0
⇒ (2x+y−1)+λ(3x+2y−5)=0
Since, this line passes through the origin also
(0+0−1)+λ(0+0−5)=0
⇒ −5λ=1⇒λ=−

1

5

Required line is
(2x+y−1)−

1

5

(3x+2y−5)=0
⇒ (2−

3

5

)x+(1−

2

5

)y−1+1=0
⇒

7

5

x+

3

5

y=0⇒7x+3y=0