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Question : 113 of 120
Marks:
+1,
-0
Solution:
=2+2+3 =−+2+ =3+, Now,
+t=(2+2+3)+(−t+2t+t‌) =(2−t)+(2+2t)+(3+t) Since,
+t is perpendicular to
(+t).=0 ⇒
[(2−t)+(2+2t)+(3+t)].(3+)=0 ⇒
3(2−1)+2+2t=0 ⇒
6−3t+2+2t=0 ⇒
t=8
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