The equation of the common tangents to the two hyperbolas \x^{2}/\a^{2}-\y^{2}/\b^{2}=1 and \y^{2}/\a^{2}-\x^{2}/\b^{2}=1 ,are

Correct Answer is : y=±x±√a2−b2

\y=\pm\x\pm\sqrt{\b^{2}-\a^{2}}

\y=\pm\x\pm\sqrt{\a^{2}-\b^{2}}

\y=\pm\x\pm\sqrt{\a^{2}+\b^{2}}

\y=\pm\x\pm\sqrt{\a^{2}-\b^{2}}

VITEEE 2010 Paper

Question : 105 of 120

Marks: +1, -0

The equation of the common tangents to the two hyperbolas

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=1 and

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=1 ,are

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