VITEEE 2009 Paper

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Question : 119 of 120

Marks: +1, -0

The solution of the differential equation

dy

dx

=sin(x+y)‌tan(x+y)−1 is

cosec(x+y)+tan(x+y)=x+c
x+cosec(x+y)=c
x+tan(x+y)=c
x+sec(x+y)=c

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