VITEEE 2009 Paper

Let the required equation of circles be
x2+y2+2‌gx+2‌fy=0
The above circle cuts the given circles orthogonally.
∴2(−3g)+2f(0)=8⇒2g=−

8

3

and -2g -2f = -7 ⇒ 2f = +7 +

8

3

=

29

3

∴ Required equation of circle is
x2+y2−

8

3

x+

29

3

y=0 or 3x2+3y2−8x+29y=0