The general solution of \sin^2\theta \sec\theta + \sqrt3 \tan\theta = O is

Correct Answer is : θ = nπ , n ∊ I

θ = nπ + (-1)^{n+1} \pi/3 , θ = nπ , n ∊ I

θ = nπ + (-1)^{n+1} \pi/3 , n ∊ I