UPSEE Solved Model Paper 7

Given :
Normality of hydrogen peroxide solution = 1.5 N
Volume strength of H2O2 can be found out by the decomposition reaction of H2O2
H2O2 decomposes as :
2H2O2 ⇌ 2H2O(l)+O2(g)
2 moles of H2O2 give 1 mole of O2
Also, 1 mole of O2 at STP occupies 22.4 L of volume
Thus, 2 moles of H2O2 give 22.4 L of O2
Basicity of H2O2 = 2
Now, molarity is given as :
Molarity =

Normality

Basicity‌of‌H2‌O2

=

1.5

2

= 0.75 M
0.75 M H2O2 has 0.75 moles of H2O2 in 1 litre of solution
2 moles of H2O2 will give = 22.4 L of O2
0.75 moles of H2O2 will give =

22.4×0.75

2

= 8.4 L of O2
Hence, option 'B' is correct