Given: Mass of N2 and Hj mixture = 340 g Yield of ammonia = 20% Reaction between N2 and H2 can be represented as: N2+3H2 → 2NH3 28 g of N2 combines with 6 g of H2 to give 34 g of NH3. N2 and H2 combine in the ratio of 28 : 6 or 14 : 3 by weight Total part by weight = 14 + 3 = 17 Now, weight of an element can be given as: Weight or an element =
Ratio‌by‌weight‌of‌element
Total‌part‌by‌weight
× Molar mas of compound Thus, Weight of nitrogen =
14
17
× 340 = 280 g Weight of hydrogen =
3
17
×340 = 60 g Now, 6g of H2 gives 34 g of NH3 Therefore, 60g of H2 will give = 34 ×