UPSEE Solved Model Paper 7

Given:
Pitch of the screw gauge, p = 1.0 mm
Number of divisions on the circular scale N = 200
For a screw gauge, the least count (LC) is
LC =

p

N

⇒ LC =

1.0mm

200

⇒ LC = 0.005 mm
⇒ LC = 5×10−3 mm
Hence, option 'C' is correct