UPSEE Solved Model Paper 7

Given:
R = {(1, 3), (2, 4), (2, 3), (3, 1)} and A = {1, 2, 3, 4}
We have relation R = {(1, 3), (2, 4), (2, 3), (3, 1)} defined on A.
Since, (1, 3), (3, 1) ∊ R but (1, 1) ∉ R,
∴ R is not transitive.
Also, (a, a) ∉ R for all a ∊ A
∴ R is not reflexive.
For (2, 4) ∊ R, (4, 2) ∉ R and for (2, 3) ∊ R, (3, 2) ∉ R
∴ R is not symmetric.
Since, (2, 4) e R and (2, 3) ∊ R.
So, R is not a function. [Since one to many mapping is not a function]
Hence, option 'C' is correct.