UPSEE Solved Model Paper 6

Here, we have to find out the given mixture of water and alcohol.
It is given,
Density of water, ρ1 = 1000 kg∕m3
Density of water, ρ2 = 800 kg∕m3
Volume of water, V1 = 1.9 m3
Volume of water, V2 = 0. 50 m3
We have,
=

ρ1V1+ρ2V2

V1+V2

=

1.9×1000+0.5×800

1.9+0.5

=

1900+400

2.4

=

2300×10

24

= 958.3
~ 950 kg∕m3
That is, the given mixture of water and alcohol is 950 kg∕m3.