UPSEE Solved Model Paper 5

There are 4 such circles, two of which have centres in first quadrant (h,h) and other two have centres in second (-h,h) and fourth quadrant (h,-h) respectively
|

4h+3h−12

5

| = h ⇒ h = 6 , 1
Radii in first quadrant
-

−4h+3h−12

5

= h ⇒ h = 3
Radius in second quadrant
-

4h−3h−12

5

= h ⇒ h = 2
Radius in second quadrant
Hence sum = 12
Alternatively

Δ

s

+

Δ

s−a

+

Δ

s−b

Δ

s−c

=

6

6

+

6

6−3

+

6

6−4

+

6

6−5

= 1 + 2 + 3 + 6 = 12