UPSEE Solved Model Paper 5

Equation of given circle is x2+y2 + 6x + 8y = 0 ... (i)
At point (1,1) S1 = 12+12 + 6 + 8 = 1 + 1 + 6 + 8 = 16
Now, radius r
r = √32+42 = 5
Area of required triangle =

rS1 3 2

r2+S1

=

5×16 3 2

52+16

=

320

41

sq unit