UPSEE Solved Model Paper 5

we have r = 0.30 m
Total distance travelled = circumference = 2πr = 2 ×

22

7

×0.30 = 1.885 m
Since 1200 revolutions are completed in one minute = 60 sec
so time taken in one revolution T =

60

1200

= 0.05 sec
Speed, v =

distance

time

=

1.885

0.05

= 37.7 m/s
∴ Acceleration of a particle at the tip of the blade is centrepetal acceleration , a =

v2

r

=

( 2πr T )2

r

=

(37.7)2

0.30

=

1421.29

0.30

= 4737.633
~ 4740 m / s2