UPSEE Solved Model Paper 4

The given circles are concentric with centre at (0, 0) and the length of the perpendicular from (0, 0) on the given line is p.
Let OL = p
Then, AL = √(OA)2−(OL)2
= √a2−p2
And PL = √(OP)2−(OL2)
= √b2−p2
⇒ AP = √a2−p2−√b2−p2