UPSEE Solved Model Paper 3

Since, the graph of t vs (a−x)−1 or

1

a−x

is a straight line, it must be a second order reaction and for a second order reaction, K =

1

t

[

1

(a−x)

−

1

a

]

1

a−x

= Kt+

1

a

On comparing, slope = K = tan θ = 0.5mol−1sin−1OA =

1

a

= 2L mol
or a = 0.5‌mol‌L−1
Rate = K(a)2 = 0.5×(0.5)2
= 0.125‌mol‌L−1‌min−1