UPSEE Solved Model Paper 3

In going from P to Q increase in kinetic energy =

1

2

m(2v)2−

1

2

mv2 =

3

2

(mv2)
= work done by electric field or

3

2

mv2 = Eq × 2a or E =

3

4

(

mv2

qa

)
= (qE) v = qv[

3

4

(

mv2

qa

)]
=

3

4

(

mv3

a

)
(as P =

dw

dE

= Fvcosθ)
At q, v is perpendicular to E and B and no work is done by either field.