If Ir means loglog...x, the log being repeated/- times, then \int\{xlogxlog^2(x)...\log^r(x)\}^{−1} dx is equal to

Correct Answer is : logr+1(x)+C

UPSEE Solved Model Paper 3

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If Ir means loglog...x, the log being repeated/- times, then ∫{xlogxlog2(x)...logr(x)}−1 dx is equal to

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