UPSEE Solved Model Paper 2

We know that Q = CV and Q = Q0 cos ωt. Also Q0 = CV0
∴ cos ωt =

Q

Q0

=

V

V0

=

6

12

=

1

2

or ωt =

π

3

.
Now ω is given by
ω =

1

√LC

(1)
Given : = 0.6 × 10−3 H and C = 2×10−6F.
Using these values in Eq. (1) we get ω =

105

2√3

‌rad‌s−1.
Now l =

dQ

dt

=

d

dt

(Q0cosωt)
= −Q0ωsinωt
∴ |I| = Q0ωsiωt = CV0ωsinωt
= (2×10−6) × 12 ×

105

2√3

sin(

π

3

)
= 0.6 A