UPSEE Solved Model Paper 2

Three capacitors are connected in series, hence their equivalent capacity will be:
Cs = C / 3 = 5 / 3.
This equivalent series capacity is then connected in parallel with the fourth capacitor, hence the final equivalent capacity will be:
Cs+C4 = 5 / 3 + 5 = 20 / 3 = 6.66 6 μF.
Now, charge on C1,C2 and C3 is same as they are in series.
It is given by: Q = Cs V = 5 / 3 x 240 = 5 x 80 x 10−6 C = 4 x 10−4 C
Charge on C4 = C4 x V = 5 x 240 = 1200 x 10−6 = 12 x 10−4 C.