UPSEE Solved Model Paper 2

Pressure at the cottom - hρg. Therefore, the force exerted at the bottom is F1 = hρg × πr2.
Now, since the mass of the liquid can be regarded as being concentrated at its centre of mass which is at a height h/2, the pressure on the sides =

h

2

ρg
Therefore, force exerted on sides is
F2 =

h

2

ρg×2πrh.
Given F1 = F2, or
hρg × πr2 =

5

2

ρg×2πrh
which gives r = h.