UPSEE Solved Model Paper 1

8 gm of helium = 8/4 = 2 mole of helium (He)
n1 = 2
28 gm of N2 = 28/28 = 1 mole of N2, n2 =1
Helium (He) is monoatomic gas
So, Cv = 3/2R and Cp = 5/2R
N2 is diatomic gas, So Cv = 5/2 Rand Cp = 7/2R
Now Cy of mixture
=

n1Cv1+n2Cv2

n1+n2

=

2 3 2 R+1 5 2 R

2+1

= 11/6R
Cp of mixture
=

n1Cp1+n2Cp2

n1+n2

=

2 5 2 R+1 7 2 R

2+1

=

17

6

R

Cp

Cv

=

17

11