UPSEE Solved Model Paper 1

Resistance of 1st bulb
r1 =

V2

P1

=

(200)2

200

r1 = 200
Resistance of IInd bulb
R2 =

(200)2

P2

=

(200)2

400

R2 = 100
When bulbs are in series with 100 V battery.
i =

(Vbattery)

R1+R2

i =

(100)

100+200

=

1

3

A
= 0.33 Amp