UPSEE Solved Model Paper 1

a1+a3+a5 = − 12
a+a+2d+a+4d = −12
a+2d = −4
a1⋅a3⋅a5 = 80
a(a+2d)(a+4d) = 80
(a)(−4)(a+4d) = 80
a(a+4d) = −20
(−4−2d)(−4+2d) = −20
4d2−16 = 20
d = ± 3 ⇒ d = + 3
Hence a = −10
So, a5 = 2