UPSEE 2019 Solved Paper

Given,
Solubility product for CaSO4(Ksp)=9.0×10−6
Gram value of CaSO4=2g
Suppose solubility of CaSO4 in water is 'S'.
CaSO4⇌

2+

Ca

(aq)+SO42−(aq)
Here, Ksp(CaSO4)=S2
S2=9.0×10−6
S=3×10−3
Molar mass of CaSO4=136
Solubility of CaSO4=3×10−3
When, 2g of CaSO4 dissolve in water.
∵ Solubility =

2

136× Volume

∴3×10−3=

2

136× Volume

Volume =

2

136×3×10−3

=

2×1000

136×3

=4.90L