UPSEE 2019 Solved Paper

Given, potential difference, V=5kV and discharge current, I=3.2mA=3.2×10.3A
As, we know that current, I=

ne

t

where, n= number of electron, e= charge on electron and t= time
⇒n=

It

e

Putting t=1s and e=1.6×10−19C
⇒n=

3.2×10−3×1

1.6×10−19

=2×1016
Hence, 2×1016 electrons are striking the target per second.