UPSEE 2019 Solved Paper

A free body diagram of a mass pully system is shown belowNow, tension in the string
T−Mg=0
⇒ T=Mg
Force in vertical direction,
F1=T+mg
⇒F1=Mg+mg=(M+m)g
Similarly, force in horizontal direction
F2=T=Mg
Now, the resultant force
Fres =√F12+F22+2F1F2‌cos‌90°
⇒Fres =√F12+F22 =√(M+m)2g2+M2g2
⇒Fres =g√(M+m)2+M2
Hence, the resultant force is g√(M+m)2+M2.