UPSEE 2019 Solved Paper

Key-Idea The efficiency of a carnot engine is given as
η=1−

T2

T1

=1−

Q2

Q1

Where, T1= source temperature, T2=sink temperature Q1= heat extracted from source and Q2= heat given to sin‌k.
Here, T1=500K,Q1=300cal and Q2=150cal
Now putting these values in above equation,
1−

T2

500

=1−

150

300

⇒ T2=500×

150

300

=250K
Hence, the temperature of sink is 250K.